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leetCode 104. Maximum Depth of Binary Tree 二叉树问题

发布时间:2020-07-04 08:54:18 来源:网络 阅读:413 作者:313119992 栏目:编程语言

104. Maximum Depth of Binary Tree


Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Minimum Depth of Binary Tree求解类似。 http://qiaopeng688.blog.51cto.com/3572484/1835237 


代码如下:

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int maxDepth(TreeNode* root) {
        int iMaxDepth = 0;
        vector<int> depths;
        stack<TreeNode *> s;
        
        TreeNode *p,*q;
        q = NULL;
        p = root;
        if(!root)
            return 0;
        while(p != NULL || s.size() > 0)
        {
            while( p != NULL)
            {
                s.push(p);
                p = p->left;
            }
            if(s.size() > 0)
            {
                p = s.top();
                 
                if( NULL == p->left && NULL == p->right)
                {
                    if(iMaxDepth < s.size())
                        iMaxDepth = s.size();
                }
                 
                if( (NULL == p->right || p->right == q) )
                {
                    q = p;
                    s.pop();
                    p = NULL;
                }
                else
                    p = p->right;
            }
        }
        return iMaxDepth;
    }
};


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